[Freeciv-Dev] Where can I get that Great Tileset?

[Erik Sigra <freeciv@xxxxxxx>]

> To: freeciv-dev@xxxxxxxxxxx 
> Subject: [Freeciv-Dev] isometric tileset screenshots
> From: Thue Janus Kristensen <thue@xxxxxxx> 
> Date: Mon, 17 Apr 2000 15:00:59 +0200 
> Sender: freeciv-dev-bounce@xxxxxxxxxxx 
>
> Tim Smith just sent me some screenshots of his isometric tileset; very
> impressive!
>
> they are at
> http://hjem.get2net.dk/thue_janus_kristensen/THUE1.GIF
> http://hjem.get2net.dk/thue_janus_kristensen/THUE2.GIF
> http://hjem.get2net.dk/thue_janus_kristensen/THUE3.GIF
> http://hjem.get2net.dk/thue_janus_kristensen/THUE4.GIF
>
> They are ours for the taking, GPL and all. Of course, someone will need

The main question: Where can I download the image sources (do I have to
mail the artist)?

> to make that isometric graphics engine (that allows units/cities
> overlapping neightboring squares). I don't think I am the best for that,
> as I have little experience in that direction, and there is a few other
> freeciv thing that need doing first.
> But if nobody else volunteers I will have to take a shot eventually :)

Here are some extra questions for you:)
* It has been a while. Is the above still your oppinion or have you
settled with the current view for good?
* What other things are before this in your job queue currently?
* When do you estimate that there will be a stable release of Freeciv
with isometric view (quarters, years, far future)?

Note: When I say isometric view, i don't mean some silly compatibility
mode like a tilted map with diagonal poles, I mean the proper civ2 way,
like this:

The coordinate system:

   /\  /\  /\  /\  /\
  /x0\/x1\/x2\/x3\/x4\
 /\y0/\y0/\y0/\y0/\y0/
/x0\/x1\/x2\/x3\/x4\/
\y1/\y1/\y1/\y1/\y1/\
 \/x0\/x1\/x2\/x3\/x4\
 /\y2/\y2/\y2/\y2/\y2/
/x0\/x1\/x2\/x3\/x4\/
\y3/\y3/\y3/\y3/\y3/\
 \/x0\/x1\/x2\/x3\/x4\
  \y4/\y4/\y4/\y4/\y4/
   \/  \/  \/  \/  \/

The coordinates of the tiles surrounding (x, y):

                    \(x, y - 2)/
                     \        /
                      \      /
                       \    /
                        \  /
if (y % 2) (x - 1, y - 1)\/(x, y - 1)
else          \(x, y - 1)/\(x + 1, y - 1)
               \        /  \        /
                \      /    \      /
                 \    /      \    /
                  \  /        \  /
         (x - 1, y)\/  (x, y)  \/(x + 1, y)
                   /\          /\
                  /  \        /  \
                 /    \      /    \
                /      \    /      \
               /        \  /        \
if (y % 2) (x - 1, y + 1)\/(x, y + 1)\
else           (x, y + 1)/\(x + 1, y + 1)
                        /  \
                       /    \
                      /      \
                     /        \
                    /(x, y + 2)\
> -Thue

-Erik