[linux-help] Re: Regular expression with grep

[bruce <bbales@xxxxxxx>]

On Wednesday 26 March 2003 05:15 pm, you wrote:
> Have you tried "sed s/.$//" ?
> Since every line has EITHER an extra space OR an extra CR character,
> you can just use the wildcard.
> Obviously if some lines just have a word with a LF following it, this
> will not work. Then you would want to consider something
> like "s/[a-zA-z]$/&!/" to add a character to the lines that don't
> already have one.
Thanks Alden.  That worked.  I did a short visual search and couldn't 
find any lines that didn't have two characters, but with 76,000 lines I 
couldn't look at all.  Now all I see have only LF.

Just for my own edification, is there any way to grep for a certain 
non-printing ascii character?  The Linux programming bible says \xyy 
would find ascii yy, for instance \x07 finds the ascii bell.  But I 
wonder if maybe that only works in perl.

bruce
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