[linux-help] Re: C help!!(OT)

[Weqaar Ali Janjua <wxjanjua@xxxxxxxxxxx>]

Hi,
   Thanx!, well thats not a HomeWork problem,  just trying to figure out 
the things, anyways I got it done with using strcpy in my second code.
Thanx,
Weqaar

At 02:18 PM 4/24/2001 -0500, you wrote:

>I looked at your code briefly. It looks like you fail to allocate memory
>to store the strings in, and don't forget that gets() is dangerous.
>Whether that is related to your problem, you'll have to figure out, but
>that's all I'll offer.
>
>Your instructor should be a good source of assistance. When it comes to
>asking questions like this on mailing lists, don't expect many answers,
>since the fine line between helping others and doing homework for others
>is difficult to discern.
>
>Good luck,
>John
>
>On Tue, 24 Apr 2001, Weqaar Ali Janjua wrote:
>
> >
> > Hello guyz,
> >
> >      This question is kinda out of the list discussion but any help 
> will be
> > greatly appreciated. Can anybody help me out with the following C
> > programming problem:
> >
> > I make a structure with some char type variables:
> > -------------------START OF CODE------------------------------
> > /*POINTER TEST*/
> > #include <stdio.h>
> >
> > //Structure Definition
> > struct weqaar {
> > char *fish;
> > char *sick;
> > };
> >
> > int main(void) {
> > struct weqaar a; //initializing variable of type 'struct weqaar'
> > struct weqaar b; //initializing variable of type 'struct weqaar'
> > struct weqaar *ptr;
> > ptr=&a;
> >
> > printf("\nenter value of a.fish:");
> > gets(a.fish);
> > printf("\nenter value of a.sick:");
> > gets(a.sick);
> > printf("%s\t%s",a.fish,a.sick);
> > printf("\n");
> > //checking the values stored in mem.
> > printf("b.fish is %s,\tb.sick is %s",b.fish,b.sick);
> > //
> > printf("\n");
> > printf("\nenter value of b.fish:");
> > gets(b.fish);
> > printf("\nenter value of b.sick:");
> > gets(b.sick);
> > printf("%s\t%s",b.fish,b.sick);
> > printf("\n");
> > printf("%s\t%s",a.fish,a.sick);
> > printf("\n");
> > printf("PTR values are: %s\t%s\n",ptr->fish,ptr->sick);
> > printf("Mem. location addresses of b.fish and b.sick are %p 
> %p",b.fish,b.sick);
> > return 0;
> > }
> > -------------------END OF CODE------------------------------
> > Now I execute the program and store some data in the variables suppose:
> > I enter 'ash' in 'a.fish' and 'dish' in 'a.sick' AND 'madonna' in 'b.fish'
> > and 'nicole' in 'b.sick' and then terminate the program.
> > When I run the program again  the commented line in my C prog. gives me 
> the
> > output "madonna    nicole", that means the values are still
> > there(structures being of storage type static) and my last line prints out
> > the memory addresses '0C5B' and 'FFF0' of variables 'b.fish' and 'b.sick'
> > and the program terminates exit(1). Then I note these addresses and write
> > another piece of code:
> > -------------------START OF CODE------------------------------
> > #include <stdio.h>
> >
> > int main(void) {
> > char *hackPtr=0xFFF0; //note that line
> > printf("%s",hackPtr);
> > return 0;
> > }
> > -------------------END OF CODE------------------------------
> > now note the line 'char *hackPtr=0xFFF0;' , I have to specify 0x before 
> the
> > address I got from the output of my first program, If I dont specify '0x'
> > the compiler takes it as a string value, my core question is how can I get
> > the accurate/in-the-form memory address as '0xFFF0'?? and how can I 
> make my
> > other program modify the value in that location???can I read the string in
> > that location with my second program???or do I have to decode the value I
> > get(maybe HEX)???? AND how can I make structure of any non-static storage
> > type?????
> > Thanx in advance,
> > Weqaar Ali Janjua
> > BECE
> > Wichita State University
> >
> >
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> >
>
>
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