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[linux-help] Re: Quick BASH/Perl Question
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To: linux-help@xxxxxxxxx
Subject: [linux-help] Re: Quick BASH/Perl Question
From: Jeff Vian <jvian@xxxxxxxxxx>
Date: Thu, 11 Jan 2001 13:00:43 -0600
Reply-to: linux-help@xxxxxxxxx

Using John's answer, the following will easily work

for fname in `ls *.log`
do
    if [ -f ${fname} ]; then
        echo "${fname} exists"
    fi
done
    
----- Original Message ----- 
From: Curtis Hawthorne <cghawthorne@xxxxxxxxx>
To: <linux-help@xxxxxxxxx>
Sent: Wednesday, January 10, 2001 6:14 PM
Subject: [linux-help] Re: Quick BASH/Perl Question


> 
> That still gives me the same error message.  In the
> directory, there are about 10 or so .log files in the
> directory, and I think that by saying *.log, the shell
> will expand it to list individually every file.  Any
> other ideas?
> 
> --- John Reinke <jmreinke@xxxxxxxxxxxxxxxxxxx> wrote:
> > 
> > On Wed, 10 Jan 2001, Curtis Hawthorne wrote:
> > 
> > > First, in BASH, how do I test for the presence of
> > any
> > > .log (*.log) file in a directory?  If I do "test
> > -a
> > > *.log" it says there's too many arguments.
> > 
> > I always use an if contruct, although I guess it's
> > technically still test:
> > 
> > if [ -f *.log ]; then
> > echo "File exists"
> > fi
> > 
> > This tests if the file exists and is a regular file,
> > you can use -d to
> > test for a directory, etc...
> > 
> > For a quicker reply, I'll let someone else answer
> > the other question,
> > since my perl is rusty at the moment.
> > 
> > 
> > > Second, in Perl what's the easiset way to grab the
> > > first letter of a string, preferably without
> > splitting
> > > the whole thing into a letter by letter array?
> > > 
> > > Thanks!
> > > 
> > > Curtis
> > 
> > 
> > -- This is the linux-help@xxxxxxxxx list.  To
> > unsubscribe,
> > visit
> >
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> > 
> 
> 
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