[linux-help] Re: Quick BASH/Perl Question

[John Reinke <jmreinke@xxxxxxxxxxxxxxxxxxx>]

Oh, I guess I didn't understand your problem. You could just something
like a for loop to operate on *.log. What do you need to do - search for
the existence of ANY .log file(s)?

John

On Wed, 10 Jan 2001, Curtis Hawthorne wrote:

> 
> That still gives me the same error message.  In the
> directory, there are about 10 or so .log files in the
> directory, and I think that by saying *.log, the shell
> will expand it to list individually every file.  Any
> other ideas?
> 
> --- John Reinke <jmreinke@xxxxxxxxxxxxxxxxxxx> wrote:
> > 
> > On Wed, 10 Jan 2001, Curtis Hawthorne wrote:
> > 
> > > First, in BASH, how do I test for the presence of
> > any
> > > .log (*.log) file in a directory?  If I do "test
> > -a
> > > *.log" it says there's too many arguments.
> > 
> > I always use an if contruct, although I guess it's
> > technically still test:
> > 
> > if [ -f *.log ]; then
> >     echo "File exists"
> > fi
> > 
> > This tests if the file exists and is a regular file,
> > you can use -d to
> > test for a directory, etc...
> > 
> > For a quicker reply, I'll let someone else answer
> > the other question,
> > since my perl is rusty at the moment.
> > 
> > 
> > > Second, in Perl what's the easiset way to grab the
> > > first letter of a string, preferably without
> > splitting
> > > the whole thing into a letter by letter array?
> > > 
> > > Thanks!
> > > 
> > > Curtis
> > 
> > 
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> >
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> 
> 
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